Rationality of Preference Relations (Preference Ordering)

A preference relation is rational if it satisfies both completeness and transitivity. This article explains the independence of these two properties, the definition of rational preferences, preference ordering, and the relationship between rational preferences and utility functions.

Independence of Completeness and Transitivity

Consider an economy with \(N\) commodities. Each alternative available to a consumer is represented by an \(N\)-dimensional vector \[
\boldsymbol{x}=\left( x_{1},\cdots,x_{N}\right) \in\mathbb{R} ^{N}.
\]The \(n\)th component \(x_{n}\) of \(\boldsymbol{x}\) represents the consumption of commodity \(n\). The set of all consumption vectors available to the consumer is represented by the consumption set \[
X\subset\mathbb{R} ^{N}.
\]A consumer facing \(X\) compares the consumption vectors in \(X\) and chooses the one that is most desirable. We formalize the consumer’s system of preferences as a binary relation \(\succsim\) on \(X\), called a preference relation. Specifically, for any two consumption vectors \(\boldsymbol{x},\boldsymbol{y}\in X\), we define \(\succsim\) so that \[
\boldsymbol{x}\succsim\boldsymbol{y}\Leftrightarrow\text{the consumer weakly prefers }\boldsymbol{x}\text{ to }\boldsymbol{y}.
\]

In consumer theory, several conditions are usually imposed on preference relations in order to analyze consumer choice systematically. We have already discussed completeness and transitivity:
\begin{align*}
& \left( a\right) \ \forall\boldsymbol{x},\boldsymbol{y}\in X:(\boldsymbol{x}\succsim\boldsymbol{y}\vee\boldsymbol{y}\succsim
\boldsymbol{x})\\
& \left( b\right) \ \forall\boldsymbol{x},\boldsymbol{y},\boldsymbol{z}\in X:\left[ (\boldsymbol{x}\succsim\boldsymbol{y}\wedge\boldsymbol{y}\succsim\boldsymbol{z})\Rightarrow\boldsymbol{x}\succsim\boldsymbol{z}\right] .
\end{align*}These two properties are independent. That is, there exist preference relations that satisfy completeness but not transitivity, and conversely, preference relations that satisfy transitivity but not completeness. The following examples illustrate this point.

Example (Completeness Without Transitivity)
Suppose a consumer compares consumption vectors in a consumption set \(X\subset\mathbb{R} ^{N}\) using two different criteria. Let \(\succsim_{1}\) denote the preference relation induced by the first criterion and \(\succsim_{2}\) the preference relation induced by the second. Suppose that both \(\succsim_{1}\) and \(\succsim_{2}\) satisfy completeness and transitivity. Define the consumer’s preference relation \(\succsim\) for arbitrary \(\boldsymbol{x},\boldsymbol{y}\in X\) by \[
\boldsymbol{x}\succsim\boldsymbol{y}\Leftrightarrow\left( \boldsymbol{x}\succsim_{1}\boldsymbol{y}\vee\boldsymbol{x}\succsim_{2}\boldsymbol{y}\right)
.
\]Thus, the consumer weakly prefers \(\boldsymbol{x}\) to \(\boldsymbol{y}\) if and only if \(\boldsymbol{x}\) is at least as desirable as \(\boldsymbol{y}\) according to at least one of the two criteria. The relation \(\succsim\) defined in this way satisfies completeness, but need not satisfy transitivity (see the exercises).
Example (Transitivity Without Completeness)
Suppose again that a consumer compares consumption vectors in a consumption set \(X\subset\mathbb{R} ^{N}\) using two different criteria. Let \(\succsim_{1}\) and \(\succsim_{2}\) denote the preference relations induced by the two criteria, and suppose that both satisfy completeness and transitivity. Define the consumer’s preference relation \(\succsim\) for arbitrary \(\boldsymbol{x},\boldsymbol{y}\in X\) by \[
\boldsymbol{x}\succsim\boldsymbol{y}\Leftrightarrow\left( \boldsymbol{x}\succsim_{1}\boldsymbol{y}\wedge\boldsymbol{x}\succsim_{2}\boldsymbol{y}\right) .
\]Thus, the consumer weakly prefers \(\boldsymbol{x}\) to \(\boldsymbol{y}\) if and only if \(\boldsymbol{x}\) is at least as desirable as \(\boldsymbol{y}\) according to both criteria. The relation \(\succsim\) defined in this way satisfies transitivity, but need not satisfy completeness (see the exercises).

 

Rational Preference Relations

The preceding discussion shows that completeness and transitivity play different roles and that neither follows from the other. Completeness requires that any two consumption vectors be comparable, whereas transitivity requires consistency across multiple pairwise comparisons. Therefore, if we want consumer preferences to satisfy a sufficiently strong form of internal consistency, it is natural to impose both conditions simultaneously.

A preference relation \(\succsim\) on a consumption set \(X\subset\mathbb{R} ^{N}\) is called a rational preference relation or a preference ordering if it satisfies both completeness and transitivity, that is, if
\begin{align*}
& \left( a\right) \ \forall\boldsymbol{x},\boldsymbol{y}\in X:(\boldsymbol{x}\succsim\boldsymbol{y}\vee\boldsymbol{y}\succsim
\boldsymbol{x})\\
& \left( b\right) \ \forall\boldsymbol{x},\boldsymbol{y},\boldsymbol{z}\in X:\left[ (\boldsymbol{x}\succsim\boldsymbol{y}\wedge\boldsymbol{y}\succsim\boldsymbol{z})\Rightarrow\boldsymbol{x}\succsim\boldsymbol{z}\right] \end{align*}both hold.

Example (Rational Preference Relation)
In a one-commodity model, suppose that a preference relation \(\succsim\) on \(\mathbb{R} _{+}\) is defined for arbitrary \(x,y\in\mathbb{R} _{+}\) by \[
x\succsim y\Leftrightarrow x\geq y.
\]Here, \(\geq\) on the right-hand side is the usual ordering of real numbers. Thus, \(\succsim\) represents the criterion “more consumption is better.” Since the usual ordering \(\geq\) satisfies both completeness and transitivity, the preference relation \(\succsim\) defined above is rational.

 

Implications of Rationality

If a preference relation \(\succsim\) on a consumption set \(X\subset\mathbb{R} ^{N}\) satisfies completeness, then for any two consumption vectors \(\boldsymbol{x},\boldsymbol{y}\in X\), exactly one of \[
\boldsymbol{x}\succ\boldsymbol{y},\quad\boldsymbol{x}\sim\boldsymbol{y},\quad\boldsymbol{y}\succ\boldsymbol{x}\]holds. If \(\succsim\) also satisfies transitivity, then the indifference relation \(\sim\) is transitive, \[
\left( a\right) \ \forall\boldsymbol{x},\boldsymbol{y},\boldsymbol{z}\in X:\left[ \left( \boldsymbol{x}\sim\boldsymbol{y}\wedge\boldsymbol{y}\sim\boldsymbol{z}\right) \Rightarrow\boldsymbol{x}\sim\boldsymbol{z}\right] ,
\]and the strict preference relation \(\succ\) is transitive, \[
\left( b\right) \ \forall\boldsymbol{x},\boldsymbol{y},\boldsymbol{z}\in X:\left[ \left( \boldsymbol{x}\succ\boldsymbol{y}\wedge\boldsymbol{y}\succ\boldsymbol{z}\right) \Rightarrow\boldsymbol{x}\succ\boldsymbol{z}\right] .
\]In addition, IP-transitivity and PI-transitivity imply
\begin{align*}
& \left( c\right) \ \forall\boldsymbol{x},\boldsymbol{y},\boldsymbol{z}\in X:\left[ \left( \boldsymbol{x}\succsim\boldsymbol{y}\wedge\boldsymbol{y}\succ\boldsymbol{z}\right) \Rightarrow\boldsymbol{x}\succ\boldsymbol{z}\right] \\
& \left( d\right) \ \forall\boldsymbol{x},\boldsymbol{y},\boldsymbol{z}\in X:\left[ \left( \boldsymbol{x}\sim\boldsymbol{y}\wedge\boldsymbol{y}\succ\boldsymbol{z}\right) \Rightarrow\boldsymbol{x}\succ\boldsymbol{z}\right] \\
& \left( e\right) \ \forall\boldsymbol{x},\boldsymbol{y},\boldsymbol{z}\in X:\left[ \left( \boldsymbol{x}\succ\boldsymbol{y}\wedge\boldsymbol{y}\succsim\boldsymbol{z}\right) \Rightarrow\boldsymbol{x}\succ\boldsymbol{z}\right] \\
& \left( f\right) \ \forall\boldsymbol{x},\boldsymbol{y},\boldsymbol{z}\in X:\left[ \left( \boldsymbol{x}\succ\boldsymbol{y}\wedge\boldsymbol{y}\sim\boldsymbol{z}\right) \Rightarrow\boldsymbol{x}\succ\boldsymbol{z}\right] .
\end{align*}What can we conclude from these properties?

Choose any two consumption vectors \(\boldsymbol{x},\boldsymbol{x}^{\prime}\in X\). By completeness, they are comparable. Choose a third consumption vector \(\boldsymbol{x}^{\prime\prime}\in X\). Again by completeness, \(\boldsymbol{x}\) and \(\boldsymbol{x}^{\prime\prime}\) are comparable, and so are \(\boldsymbol{x}^{\prime}\) and \(\boldsymbol{x}^{\prime\prime}\). Hence any two of the three vectors are comparable. Moreover, by transitivity of \(\sim\) and \(\succ\), together with IP-transitivity and PI-transitivity, they can be ordered consistently in terms of \(\succ\) and \(\sim\) without generating cycles. The same reasoning applies to any further consumption vectors. Therefore, if \(\succsim\) is rational, any elements of the consumption set \(X\) can be positioned consistently in terms of their relative desirability using \(\succ\) and \(\sim\), without contradiction or cycles.
 

Utility Functions Representing Rational Preferences

A preference relation \(\succsim\) on a consumption set \(X\) is rational if and only if both \begin{align*}
& \left( a\right) \ \forall\boldsymbol{x},\boldsymbol{y}\in X:\left(
\boldsymbol{x}\succsim\boldsymbol{y}\vee\boldsymbol{y}\succsim\boldsymbol{x}\right) \\
& \left( b\right) \ \forall\boldsymbol{x},\boldsymbol{y},\boldsymbol{z}\in X:\left[ (\boldsymbol{x}\succsim\boldsymbol{y}\wedge\boldsymbol{y}\succsim\boldsymbol{z})\Rightarrow\boldsymbol{x}\succsim\boldsymbol{z}\right] \end{align*}hold. Suppose there exists a utility function \(u:X\rightarrow\mathbb{R} \) representing \(\succsim\). By the definition of a utility function, conditions (a) and (b) are respectively equivalent to \begin{align*}
& \left( a^{\prime}\right) \ \forall\boldsymbol{x},\boldsymbol{y}\in X:\left[ u\left( \boldsymbol{x}\right) \geq u\left( \boldsymbol{y}\right)
\vee u\left( \boldsymbol{y}\right) \geq u\left( \boldsymbol{x}\right)
\right] \\
& \left( b^{\prime}\right) \ \forall\boldsymbol{x},\boldsymbol{y},\boldsymbol{z}\in X:\left\{ \left[ u\left( \boldsymbol{x}\right) \geq u\left( \boldsymbol{y}\right) \wedge u\left( \boldsymbol{y}\right) \geq u\left( \boldsymbol{z}\right) \right] \Rightarrow u\left( \boldsymbol{x}\right) \geq u\left( \boldsymbol{z}\right) \right\} .
\end{align*}

Proposition (Characterizing Rationality Using a Utility Function)
Suppose that there exists a utility function \(u:X\rightarrow\mathbb{R} \) representing a preference relation \(\succsim\) on \(X\subset\mathbb{R} ^{N}\). Then \(\succsim\) is rational if and only if \begin{align*}
& \left( a\right) \ \forall\boldsymbol{x},\boldsymbol{y}\in X:\left[
u\left( \boldsymbol{x}\right) \geq u\left( \boldsymbol{y}\right) \vee u\left( \boldsymbol{y}\right) \geq u\left( \boldsymbol{x}\right) \right] \\
& \left( b\right) \ \forall\boldsymbol{x},\boldsymbol{y},\boldsymbol{z}\in X:\left\{ \left[ u\left( \boldsymbol{x}\right) \geq u\left(
\boldsymbol{y}\right) \wedge u\left( \boldsymbol{y}\right) \geq u\left(
\boldsymbol{z}\right) \right] \Rightarrow u\left( \boldsymbol{x}\right)
\geq u\left( \boldsymbol{z}\right) \right\}
\end{align*}both hold.

The usual ordering \(\geq\) on the real numbers satisfies completeness and transitivity: \begin{align*}
& \left( a\right) \ \forall a,b\in\mathbb{R} :\left( a\geq b\vee b\geq a\right) \\
& \left( b\right) \ \forall a,b,c\in\mathbb{R} :\left[ \left( a\geq b\wedge b\geq c\right) \Rightarrow a\geq c\right] .
\end{align*}Therefore, any real-valued function \(u:X\rightarrow\mathbb{R}\) satisfies \begin{align*}
& \left( a\right) \ \forall\boldsymbol{x},\boldsymbol{y}\in X:\left[
u\left( \boldsymbol{x}\right) \geq u\left( \boldsymbol{y}\right) \vee u\left( \boldsymbol{y}\right) \geq u\left( \boldsymbol{x}\right) \right] \\
& \left( b\right) \ \forall\boldsymbol{x},\boldsymbol{y},\boldsymbol{z}\in X:\left\{ \left[ u\left( \boldsymbol{x}\right) \geq u\left(
\boldsymbol{y}\right) \wedge u\left( \boldsymbol{y}\right) \geq u\left(
\boldsymbol{z}\right) \right] \Rightarrow u\left( \boldsymbol{x}\right)
\geq u\left( \boldsymbol{z}\right) \right\} .
\end{align*}Hence, if a utility function representing \(\succsim\) exists, then the preceding conditions automatically hold, and the proposition above implies that \(\succsim\) is rational. In other words, a utility function representing a preference relation need not exist in general, but whenever one does exist, the represented preference relation is guaranteed to be rational.

Proposition (Rationality of Preferences Represented by a Utility Function)
If there exists a utility function \(u:X\rightarrow\mathbb{R} \) representing a preference relation \(\succsim\) on \(X\subset\mathbb{R} ^{N}\), then \(\succsim\) is rational.

The converse need not hold. Even if a preference relation \(\succsim\) is rational, there need not exist a utility function representing it. Conditions for the existence of a utility representation will be discussed in detail elsewhere.
 

Exercises

Problem (Utility Representation of a Nonrational Preference Relation)
Suppose a preference relation \(\succsim\) defined on a consumption set \(X\subset\mathbb{R} ^{N}\) is not rational. Prove that there does not exist a utility function \(u:X\rightarrow\mathbb{R} \) representing \(\succsim\).
View Solution

Members-Only Content
【Log In】【Sign Up】

Problem (A Preference Relation That Need Not Be Rational)
Suppose a consumer compares consumption vectors in \(X\subset\mathbb{R} ^{N}\) using two different criteria. Let \(\succsim_{1}\) and \(\succsim_{2}\) denote the preference relations induced by the first and second criteria, respectively, and suppose that both satisfy completeness and transitivity. Define \(\succsim\) for arbitrary \(\boldsymbol{x},\boldsymbol{y}\in X\) by \[
\boldsymbol{x}\succsim\boldsymbol{y}\Leftrightarrow\left( \boldsymbol{x}\succsim_{1}\boldsymbol{y}\vee\boldsymbol{x}\succsim_{2}\boldsymbol{y}\right)
.
\]Show that \(\succsim\) satisfies completeness but need not satisfy transitivity.
View Solution

Members-Only Content
【Log In】【Sign Up】

Problem (A Preference Relation That Need Not Be Rational)
Suppose a consumer compares consumption vectors in \(X\subset\mathbb{R} ^{N}\) using two different criteria. Let \(\succsim_{1}\) and \(\succsim_{2}\) denote the preference relations induced by the two criteria, and suppose both satisfy completeness and transitivity. Define \(\succsim\) for arbitrary \(\boldsymbol{x},\boldsymbol{y}\in X\) by \[
\boldsymbol{x}\succsim\boldsymbol{y}\Leftrightarrow\left( \boldsymbol{x}\succsim_{1}\boldsymbol{y}\wedge\boldsymbol{x}\succsim_{2}\boldsymbol{y}\right) .
\]Show that \(\succsim\) satisfies transitivity but need not satisfy completeness.
View Solution

Members-Only Content
【Log In】【Sign Up】

Problem (Rational Preferences)
In a two-commodity model, suppose that a preference relation \(\succsim\) on \(\mathbb{R}_{+}^{2}\) is rational. Determine whether each of the following statements is true or false, and explain your answer.

  1. Any two consumption vectors \(\left( x_{1},x_{2}\right) \) and \(\left( y_{1},y_{2}\right) \) can always be compared under \(\succsim\).
  2. For any three consumption vectors \(\left( x_{1},x_{2}\right) \), \(\left( y_{1},y_{2}\right) \), and \(\left( z_{1},z_{2}\right) \), if \[
    \left( x_{1},x_{2}\right) \succ\left( y_{1},y_{2}\right)
    \]and
    \[
    \left( x_{1},x_{2}\right) \succ\left( z_{1},z_{2}\right)
    \]both hold, then
    \[
    \left( y_{1},y_{2}\right) \succ\left( z_{1},z_{2}\right)
    \]must also hold.

  3. For any two quantities \(x_{1}\) and \(x_{2}\), the option of consuming \(x_{1}\) units of commodity \(1\) and the option of consuming \(x_{2}\) units of commodity \(2\) can always be compared under \(\succsim\).
View Solution

Members-Only Content
【Log In】【Sign Up】

Problem (Rationality of Preferences Represented by a Utility Function)
In a two-commodity model, let the consumption set be \(\mathbb{R}_{+}^{2}\), and define a preference relation \(\succsim\) for arbitrary \(\left( x_{1},x_{2}\right) ,\left( y_{1},y_{2}\right) \in\mathbb{R} _{+}^{2}\) by \[
\left( x_{1},x_{2}\right) \succsim\left( y_{1},y_{2}\right)
\Leftrightarrow x_{1}+2x_{2}\geq y_{1}+2y_{2}.
\]Prove that this preference relation is rational.
View Solution

Members-Only Content
【Log In】【Sign Up】

Discussion

To ask questions about this material or discuss it with other learners, you need to register as a member and log in.

  • Members can post comments
  • You can reply to other users
  • You can search and view past discussions
  • You can edit your posts later

At WIIS, we believe that all users are equal as learners, regardless of age, gender, educational background, occupation, or social status.

This is not a place to compete over knowledge, but a space to deepen understanding while respecting one another’s ideas. Questions and opinions are welcome, and you are also encouraged to ask openly about anything you do not understand.

To help maintain a constructive and welcoming learning environment, please review the guidelines before posting.

If you find a typo, broken link, or error in the content, please let us know using the form below.

Ask AI
WIIS AI Tutor ×
Checking today's usage...
Hello! I am the AI tutor for this material. Ask me about proofs, concepts, calculations, or anything else related to this page.

💡 Select text or equations on the page to quote them automatically in the input box below.

Table of Contents

MEMBERSHIP

Take your learning further.

Join WIIS to access
members-only content,
downloadable PDF textbooks,
AI Tutor, forums,
and other member benefits.

MEMBERS-ONLY CONTENT

Access exclusive materials designed for deeper learning.

PDF TEXTBOOKS

Download textbooks and study them anywhere.

AI Tutor

Use AI-powered support to deepen your understanding.

COMMUNITY FEATURES

Connect with other learners and join discussions and research.

Recently Viewed Pages